English, asked by virendraswami, 2 months ago

if speed of sound S depends on mass of aire atmospheric principal density of air D then find firmula​

Answers

Answered by sohamdutta56
0

Answer:

speed of sound is 3•8×10⅞

speed of sound=speed of sound in air/speed in medium

s/d

i tred but above all it is √

Answered by qismatrani33gmailcom
0

Answer:

The speed of sound is the distance travelled per unit of time by a sound wave as it propagates through an elastic medium. At 20 °C (68 °F), the speed of sound in air is about 343 metres per second (1,235 km/h; 1,125 ft/s; 767 mph; 667 kn), or a kilometre in 2.9 s or a mile in 4.7 s. It depends strongly on temperature as well as the medium through which a sound wave is propagating.

Sound measurements

Characteristic Symbol

Sound pressure p, SPL,LPA

Particle velocity v, SVL

Particle displacement δ

Sound intensity I, SIL

Sound power P, SWL, LWA

Sound energy W

Sound energy density w

Sound exposure E, SEL

Acoustic impedance Z

Audio frequency AF

Transmission loss TL

Approximation of the speed of sound in dry air based on the heat capacity ratio (in green) against the truncated Taylor expansion (in red).

The approximate speed of sound in dry (0% humidity) air, in metres per second, at temperatures near 0 °C, can be calculated from

{\displaystyle c_{\mathrm {air} }=(331.3+0.606\cdot \vartheta )~~~\mathrm {m/s} ,}{\displaystyle c_{\mathrm {air} }=(331.3+0.606\cdot \vartheta )~~~\mathrm {m/s} ,}

where {\displaystyle \vartheta }\vartheta is the temperature in degrees Celsius (°C).[9]

This equation is derived from the first two terms of the Taylor expansion of the following more accurate equation:

{\displaystyle c_{\mathrm {air} }=331.3~{\sqrt {1+{\frac {\vartheta }{273.15}}}}~~~~\mathrm {m/s} .}{\displaystyle c_{\mathrm {air} }=331.3~{\sqrt {1+{\frac {\vartheta }{273.15}}}}~~~~\mathrm {m/s} .}

Dividing the first part, and multiplying the second part, on the right hand side, by √273.15 gives the exactly equivalent form

{\displaystyle c_{\mathrm {air} }=20.05~{\sqrt {\vartheta +273.15}}~~~~\mathrm {m/s} .}{\displaystyle c_{\mathrm {air} }=20.05~{\sqrt {\vartheta +273.15}}~~~~\mathrm {m/s} .}

which can also be written as

{\displaystyle c_{\mathrm {air} }=20.05~{\sqrt {T}}~~~~\mathrm {m/s} }{\displaystyle c_{\mathrm {air} }=20.05~{\sqrt {T}}~~~~\mathrm {m/s} }

where T denotes the thermodynamic temperature.

The value of 331.3 m/s, which represents the speed at 0 °C (or 273.15 K), is based on theoretical (and some measured) values of the heat capacity ratio, γ, as well as on the fact that at 1 atm real air is very well described by the ideal gas approximation. Commonly found values for the speed of sound at 0 °C may vary from 331.2 to 331.6 due to the assumptions made when it is calculated. If ideal gas γ is assumed to be 7/5 = 1.4 exactly, the 0 °C speed is calculated (see section below) to be 331.3 m/s, the coefficient used above.

Explanation:

... I hope it will be helpful for you..

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