Question

if speed v and time t are related as t^2-10vt+10000=0 then what can be the value of y​. Pls give full solution.

Answer 1

Answer:

Answer

Correct option is

D

14 m/s

2

Velocity when t=2s is v

2

=10+2×4=18m/s

Velocity when t=5s is v

5

=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a=

Δt

Δv

=

3s

42m/5

=14m/s

2

Explanation:

if