Question

If sq. root of 2 = 1.41 and sq. root of 3 = 1.73
Then value of sq. root of 216 is

Answer 1

Answer:

14.64

Step-by-step explanation:

$\sqrt{216}\\= \sqrt{6^3}\\= 6\sqrt{6} \\= 6* \sqrt{3} * \sqrt{2}\\= 6 * 1.41 * 1.73\\= 14.64 ( rounded upto 2 decimal places)$

Answer 2

Answer:

$\sqrt{216}$ = 14.6358

Step-by-step explanation:

Given,

√2 = 1.41

√3 = 1.73

To find,

$\sqrt{216}$

Solution:

The prime factorization of 216 = 2×2×2×3×3×3

216 = 2×2×2×3×3×3

216 = 2²×2×3²×3

$\sqrt{216}$ = $\sqrt{2^2X2X3^2X3}$ = 2×3×√2×√3

$\sqrt{216}$ = 6×√2×√3

=  6×1.41×1.73 (∵ given√2 = 1.41 and √3 = 1.73)

= 14.6358

∴ $\sqrt{216}$ = 14.6358

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