Question

if square root 2 is 1.414 and square root of 5 is 2.236 and square root of 3 is 1.732 find square root of 72+square root of 48

Answer 1

$\sqrt{72} + \sqrt{48}$

$= 6 \sqrt{2} + 4 \sqrt{3}$

$= 6 \times 1.41 + 4 \times 1.73$


$= 8.46 + 6.92$

$= 15.38$


Thanks

Answer 2

$\sqrt{72} + \sqrt{48}$
=
$\sqrt{2 \times 2 \times 2 \times 3 \times 3} + \sqrt{2 \times 2 \times 2 \times 2 \times 3}$
=
$6 \sqrt{2} + 4 \sqrt{3}$
(6x1.414) + (4x1.732)
=15.412