Question

If square root of 1369+square root 0.0615+x = 37.25 and x=1/10^y , then the value of y is

Answer 1

Answer:

Step-by-step explanation:

0.0615+x

=0.0615x

37.25/1x10=y

Y=372.5

Answer 2

If square root of 1369+square root 0.0615+x = 37.25 and x=1/10^y, then the value of y is 3.

Step-by-step explanation:

Given data: √[1369] + √[0.0615 + x] = 37.25 and x = 1/10^y

To find: the value of y

Solution:  

√[1369] + √[0.0615 + x] = 37.25  

⇒ 37 + √[0.0615 + x] = 37.25  

⇒ √[0.0615 + x] = 37.25 – 37

⇒ √[0.0615 + x] = 0.25

squaring on both sides

⇒ 0.0615 + x = 0.0625

⇒ x = 0.0625 – 0.0615

⇒ x = 1 * 10⁻³

Since we are given  

x = 1/10^y

∴ 1 * 10⁻³ = 1/10^y

⇒ 10⁻³ = 10^-y

⇒ y = 3

Thus, the value of y is 3.

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