Math, asked by mithilarajakumar8, 1 year ago

If square root of a is an integer and ab2= 100, how many values are possible for integer b ?


mithilarajakumar8: The answer is given as 8

Answers

Answered by achaldoshi23
4

Answer: 10/√x


Step-by-step explanation:

a^2 = x

X is an integer

(ab)^2 = 100

a^2 * b^2 = 100

x * b^2 = 100

b^2 = 100/x

b = √100/√x

b = 10/√x




mithilarajakumar8: The answer options are 2, 3, 4, 6, 8
mithilarajakumar8: It is a^(1/2)
danishk08: 4 is the answer
mithilarajakumar8: Can u explain?
mithilarajakumar8: Please
danishk08: let root a =x....... given:ab^2=100.......square rooting both sides.......give=root a×b=10......x×b=10......b=10/x......possibilities are 1,2,5,10
mithilarajakumar8: Thank you
Answered by avinashavi2580
4

Answer:

wkt, root a is an integer, ab2= 100, square root on both sides gives root a* b= 10 choose integer value for a as 1, 4, 16, 25, 100, 400, 2500, 10000 and finally possible integer values for b are totally 8

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