Question

If squerroot2^n=1024 find 3^2 (n/4-4)

Answer 1

$\sqrt{ {2}^{n} } = 1024 \\ \\ {2}^{ \frac{n}{2} } = 1024 \\ \\ {2}^{ \frac{n}{2} } = {2}^{10} \\ \\ \frac{n}{2} = 10 \\ \\ n = 20$

Now,

${3}^{2( \frac{n}{4} - 4) }\\\\ {3}^{2( \frac{20}{4} - 4 )} \\ \\ {3}^{2(5 - 4)} \\ \\ {3}^{2(1)} \\ \\ {3}^{2} = 9$