If SRP = 40° and Angle QSP = 110° , then find angle PSQ
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➤ Given that, SRP=40,
QSP=100
PSQ=?
Since, it is a trapezium, so PS is parallel To QR,
So, area PQS=area QRS, (triangle on the same base and between the same parallels have equal areas)
So, SRP=PQS=40
by angle sum property in the triangle QPS,
40+110+PSQ= 180
150+PSQ=180
PSQ=180-150
➤PSQ=30
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