If ST||RQ,PS=3 cm and SR=4cm. find the ratio of the area of triangle PST to the area of triangle triangle PRQ
Answers
Answered by
1
since ST || RQ
therefore
PS/SR =PT/TQ (By thales theorem)
in triangle PST and PRQ
PS/SR=PT/TQ (proved above)
angle P= angle P (common)
therefore, by SAS Triangle PST ~ PRQ
ar (PST)/ar (PRQ)=(PS/SR)^2
=> (3/4)^2
=>9/16
therefore
PS/SR =PT/TQ (By thales theorem)
in triangle PST and PRQ
PS/SR=PT/TQ (proved above)
angle P= angle P (common)
therefore, by SAS Triangle PST ~ PRQ
ar (PST)/ar (PRQ)=(PS/SR)^2
=> (3/4)^2
=>9/16
Answered by
0
Answer:
9:49
Step-by-step explanation:
Given
ST || RQ
PS= 3 cm
SR = 4cm
Proof :--
ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²
ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²
ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49
Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49
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