IF ‘+’ stands for ‘-‘ , ‘-‘ stands for ‘x’, ’x’ stands for ‘÷’and ‘÷’stands for ‘+’then what is the value of 56x7÷13-11+15-8÷2-7?
Answers
Answer:-
your answer is 37.1538461538
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Given:
A mathematical operation 56x7÷13-11+15-8÷2-7, in which '+’ stands for ‘-‘, ‘-‘ stands for ‘x’, ’x’ stands for ‘÷’and ‘÷’stands for ‘+’.
To Find:
The value of the operation after calculating as per the given conditions is?
Solution:
1. The given operation is 56x7÷13-11+15-8÷2-7.
2. As '+’ stands for ‘-‘, ‘-‘ stands for ‘x’, ’x’ stands for ‘÷’and ‘÷’stands for ‘+’, convert the operation accordingly,
=> The operation now becomes, 56 ÷ 7 + 13 x 11 - 15 x 8 + 2 x 7,
3. The above operation can now be solved using BODMAS,
=> The BODMAS rule states that the order of calculation that should be followed while calculating the operations that involves multiple signs like Brackets, Addition, Division, Subtraction, etc.
4. Solving the given operation,
=> 56 ÷ 7 + 13 x 11 - 15 x 8 + 2 x 7, ( Division has higher priority)
=> 8 + 13 x 11 - 15 x 8 + 2 x 7, ( Multiplication has higher priority )
=> 8 + 143 - 120 + 14, ( Addtion has higher priority )
=> 151 + 14 - 120, ( Addition has higer priority )
=> 165 - 120,
=> 45.
Therefore, the value of the given operation after the conversion of the signs is 45.