If successive ionisation energies of an element are 7.9 eV, 13.2 eV and 247.8 eV respectively, the element is expected to be
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Given info : If successive ionisation energies of an element are 7.9 eV, 13.2 eV and 247.8 eV respectively.
To find : the element is expected to be ..
solution : ionisation enthalpy is the minimum amount of energy required to remove an electron from its gaseous state.
here successive ionisation energies of an element are 7.9 eV , 13.2 eV and 247.8 eV respectively.
from this data, it is clear that first and second electrons from outer shell are easily removable but the 3rd one needs comparatively very high amount of energy.
Indirectly it indicates that there are only two electrons present in the outermost shell of the given element. it means, the valency of the element is 2.
therefore the element is expected to be divalent.
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