Question

if successive ionization energies of an element are 7.9 EV, 13.2 EV and 240 7.8 EV respectively the element is expected to be​

Answer 1

As per the question, successive ionization energies of an element are 7.9 eV, 13.2 eV and 247.8 eV.

So, we can see :

• After releasing 2 electrons in succession, the ion has to expend a lot of energy (247.8 eV) to release the 3rd electron.

• This means that after releasing 2 electrons, the ion reached NOBLE GAS CONFIGURATION (noble gases have high $I_{E}$ values).

• So, valency of element has to be 2.

In the given options, Calcium (Ca) has valency 2, so it will be the best answer ✔️

Answer 2

Answer:Ca

Explanation: