if sum and product of a quad polynomial are -1/12 and-1/2 respectively then find the quad polynomial
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Answered by
0
Answer:
Step-by-step explanation:
The general quadratic equation is:
x^2 - ( \text{ sum of zeros } )x + \text{ product of zeros } = 0
From given,
\text{Sum of zeros } = \sqrt{2} \\\\\text{Product of zeros } = \frac{1}{3}
Therefore, the quadratic equation is given as:
x^2 - \sqrt{2}x + \frac{1}{3} = 0\\\\3x^2 - 3\sqrt{2}x + 1 = 0
Thus the required polynomial is found.
Answered by
1
Answer:
Step-by-step explanation:
The general quadratic equation is:
x^2 - (\text{ sum of zeros } )x + \text{ product of zeros } = 0
From given,
\text{Sum of zeros } = \sqrt{2} \\\\\text{Product of zeros ] = \frac{1}{3}
Therefore, the quadratic equation is given
as:
x^2 - \sqrt{2}x + \frac{1}{3} = O\\\\3x^2 -
3\sqrt{2}x + 1 = 0
Thus the required polynomial is found.
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