Question

If sum and product of two zeroes of the polynomial x3+x2-3x-3 are 0 and 3 respectively find all the zeroes of the polynomial

Answer 1

$\alpha + \beta = 0 \\ \alpha \beta = 3 \\ x {}^{3} + x {}^{2} - 3x - 3 \\ x { }^{2} - ( \alpha + \beta )x + \alpha \beta \\ x {}^{2} - 3$
[ x^3 +x^2 -3x -3]÷ [x^2 -3]
x+1 = 0
x= -1

Answer 2

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Let me know if I did it in the correct way