If sum and product of two zeroes of the polynomial x3+x2-3x-3 are 0 and 3
respectively, find all zeroes of the polynomial.
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find the value of x randomly for which the poly. becomes 0
the value is -1
thus the factor is (x+1)
divide the poly.
the result is
a=bq+r
x3+x2-3x-3=(x+1)(x2-3)+0
=(x+1)(x+root3)(x-root3)
therefore the zeroes are
-1,root3 and -root3
the value is -1
thus the factor is (x+1)
divide the poly.
the result is
a=bq+r
x3+x2-3x-3=(x+1)(x2-3)+0
=(x+1)(x+root3)(x-root3)
therefore the zeroes are
-1,root3 and -root3
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0
Answer:
sir can you please confirm that you telling to the one who write these nonsense question or me
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