if sum and product of two zeroes of x⁴-4x³-8x²+36x-9 are 0 and - 9 respectively. find the sum and product of its other two zeroes..
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sum of all four zeros=-(-4)/1=4
sum of remaing two zeros=4-0=4
product of all 4 zeros=-9
product of remaining two zeros=(-9)/(-9=1
sum of remaing two zeros=4-0=4
product of all 4 zeros=-9
product of remaining two zeros=(-9)/(-9=1
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