Question

If sum and product of zeroes of quadratic
polynomial are, respectively 8 and 12, then find
their zeroes
​

Answer 1

Answer:

general formula of quadratic polynomial

x²-(sum of zeros)x+ product of zeros

x²-(8)x +(12)

x²-8x+12

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Answer 2

Answer:

2 and 6 are the zeroes of the polynomial.

Step-by-step explanation:

Given: Sum fo zeroes = (α+β)=8

Product of the zeroes = αβ=12

Required quadratic polynomial is

= x^2 − (α+β) x + αβ

= x^2− (8)x + 12

Now , find the zeroes of the above polynomial.

Let f(x) =x^2 −(8)x + 12

= x^2 − 6x −2x + 12

=(x−6) (x−2)

Substitute f(x)=0

(x−6)=0 or (x−2)=0

⇒x = 6 or x = 2

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