Question

If sum of ₹ 1000 amount to ₹ 1331.. see ques. in picture.. solve my frnd❤️

Answer 1

$\underline{ \underline{ \bold{ \red{SOLUTION \: \: WITH \: \: EXPLAINTION \: \: \: }}}}$

$\underline{ \bold{Given \: : }} \\ \\ \bold{Principal \:, \: (P) =Rs. \: 1000} \\ \\ \bold{Amount \:, \: (A) = Rs. \: 1331} \\ \\ \bold{Time \:, \: (n) = 3 \: \: years} \\ \\ \\ \underline{\bold{To \: \: find \: :}} \: \: \: \: \bold{Rate \: \: of \: \: interest \:, \: (r)= ?\: }$

$\bold{We \: \: know \: \: that} \\ \\ \bold{A = P(1 + \frac{r}{100}) {}^{n} } \\ \\ \bold{ = > 1331 =1000(1 + \frac{r}{100} ) {}^{ 3 } } \\ \\ \bold{ = > \frac{1331}{1000} = (1 + \frac{r}{100} ) {}^{3} } \\ \\ \bold{ = > ( \frac{11}{10} ) {}^{3} = (1 + \frac{r}{100} ) {}^{3} } \\ \\ \bold{ = > \frac{11}{10} = 1 + \frac{r}{100} } \\ \\ = > \bold{ \frac{r}{100} = \frac{11}{10} - 1 } \\ \\ \bold{ = > \frac{r}{100} = \frac{1}{10} } \\ \\ \bold{ = > 10r = 100} \\ \\ \bold{ = > r = \frac{100}{10} } \\ \\ \bold{ = > r = 10} \\ \\ \bold{So ,\: \: the \: \: rate \: \: of \: \: interest = 10\% \: p.a.}$


$\underline{\huge{\bold{\red{ANSWER}}}}$ ➡

$\bold{If \: \: the \: \: sum \: \: Rs. \: 1000\: \: amount \: \: to } \\ \bold{Rs. \: 1331 \: \: in \: \: 3 \: \: years \: ,\: compounded} \\ \bold{annually \: ;\: then \: \: the \: \: rate \: \: of \: \: interest} \\ \bold{per \: \: annum \: \: \: will \: \: be \: \: 10\% \: .}$

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✝$\mathfrak{\red{THANSK...}}$✝