Question

if sum of 17 distinct natural numbers is 200,then what is the maximum possible number among those.?

Answer 1

I think such a question was answered by me a long while ago.

Here are 17 distinct numbers, so any of them are not equal to the others.

To find the answer, there's only a simple thing to do.

Among the 17 numbers, let 16 numbers have the values of natural numbers from 1 to 16.

Then add their sum.

We get 1 + 2 + 3 + ... + 16 = 136.

Subtract this from the sum, i.e., 200.

200 - 136 = 64.

So 64 is the largest possible number.

 

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Why 64?

Assume 65 is the largest possible number. When 65 becomes, 1 should be subtracted from the one among the other 16 numbers. Afterwards, the reduced number will be equal to any other number. So the numbers won't be distinct no more.

E.g.: Assume 65 is the largest. So, the other numbers are from 1 to 16. Suppose 1 is reduced from 16. It becomes 15. But there's already a 15. So the all numbers won't be distinct no more. So do other numbers.

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Hope this may be helpful.

Please mark my answer as the brainliest if this may be helpful.

Thank you. Have a nice day. :-))

   

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