Question

If sum of 25th term is 100 then find 13th term​

Answer 1

Answer:

25(13):325 multiple 25 by 13 the term below

Answer 2

Answer:

S25=n/2(2a+(n-1)d)

S25=25/2(2a+(25-1)d)

100=25/2(2a+24)d

100×2=25(2a+ 24)d

200= 50a+ 600d

600d=50a-200

d =50a-200

600

d=50a-2

6

Now, given=》S25=100, d=50a-2 , n=13

6

a13= a+(13-1)50a-2

6

6a13=a+12(50a-2)

6a13=a+600a-2

6a13=601a-2

a13=601a-2

6

a13= ?