if sum of 3rd and 8th terms of an ap is 7 and the sum of 7th and 14 th terms is -3 , find 10th term
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Step-by-step explanation:
a3 + a8 = 7
a+2d + a+7d=7
2a+9d=7. - eqn1
a7+a14=-3
a+6d a+13d=-3
2a+19d=-3. -eqn2
eliminate eqn 1 & 2
2a+19d=-3
2a+9d=7
-. - -
10d=-10
d=-1
2a+9d=7
2a-9=7
a=8
a10= a+9d
= 8-9
=-1
hence proved
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