Question

If sum of 4 consecutive natural odd numbers is 32 than find smallest number 1]5 2]4 3]15 4]10​

Answer 1

Answer:

Sum of four consecutive odd numbers:

(2a - 3) + (2a - 1) + (2a + 1) + (2a + 3) = 8a

Sum of three consecutive even numbers:

(2b - 2) + 2b + (2b + 2) = 6b

Given 8a = 6b or a/b = 3/4, a and b can be any integers. So, 'a' has to be a multiple of 3 and 'b' has to be a multiple of 4. Possible solutions are: a = 3, b = 4; a = 6, b = 8; a = 9, b = 12 etc

Since 101 < 2b < 200 i.e.

51 <= b < 100

Since b also has to be a multiple of 4, the values that b can take are 52, 56, 60, 64 ... 96

Number of values b can take = (Last term - First term)/Common Difference + 1 = (96 - 52)/4 + 1 = 12

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Step-by-step explanation:

Kashuuu~

Answer 2

Let x be the smallest ode no. Then 4 consecutive ode no. Are x,x+2,x+4,x+6