If sum of 4 successive odd whole numbers is 968 then find the least number in that
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Answer: 239
Let the 4 successive odd whole numbers are x, x+2, x +4, x+6
Sum of the numbers are 968
A/q
x + x+2 +x +4 + x+6 = 968
=> 4x + 12 = 968
=> 4x = 968 -12
=> 4x = 956
=> x = 956/4
=> x = 239
Therefore the least numer is 239 .
Step-by-step explanation:
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