Question

if sum of 5 numbers in
ap is 40 then find the middle term

Answer 1

Given AP is 20,16,12.............[-176]
Here a = 20, d = 16 – 20 = – 4
tn = –176
nth term of an AP is tn = a + (n – 1)d
⇒ –176 = 20 + (n – 1)(– 4)
⇒ –176 = 20 – 4n + 4
⇒ –176 = 24 – 4n
⇒ –176 – 24 = –4n
⇒ –200 = – 4n
∴ n = 50
The middle terms are 25th and 26th terms
t25 = 20 + (25 – 1)(– 4)
= 20 – 96 = –76
t26 = 20 + (26 – 1)(– 4)
= 20 – 100 = –80

Answer 2

The sum of the 5numbers is 40 then,
let, the no. be x
x:: 40/5
x:: 8
then, the middle term is
:::: 5