If sum of an A.P 1, 4, 7, 10,...,x is 287 then find the value of x.
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Answer:
x=40
Step-by-step explanation:
1, 4, 7, 10,...,x
a=1,d=4-1=3
let the sum of n terms=287
287=n/2( 2*1+(n-1)*3)
2*287=n( 2+3n-3)
574=3n²-n
3n²-n-574=0
n={ 1 ±√(1+4*3*574}/6
=(1 ±√6889)/6
=34±83)/6
Rejecting negative vlaue
n=(1+83)/=54/6=14
Hence x is 14th term
x=1+13*3
=1+39=40
x=40
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