if sum of first n terms of an A.P (3n²/2+5n/2)find it's nth term and it's 25th term
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sum of first n terms 3n^2/2+5n/2
for n=1,the first term is 3/2+5/2=4
for n=2,the sum of first two term is
6+5=11
so the common difference
11-(4+4)=3
it's n th term is 4+(n-1)3=4+3n-3=3n+1
it's 25 th term is 4+24.3=4+72=76
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