if sum of four consecutive integer is 46, then the four integer are
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Hey!
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Let the first consecutive number be x
Then the successive consecutive Numbers are ,
x , ( x + 1 ) , ( x + 2 ) , ( x + 3 )
Now, According to the given question:
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= x + x + 1 + x + 2 + x + 3 = 46
4x + 6 = 46
4x = 46 - 6
4x = 40
x = 40/4
↪x = 10
◾Hence the Integers are 10 , 11 , 12 and 13 respectively.
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------
Let the first consecutive number be x
Then the successive consecutive Numbers are ,
x , ( x + 1 ) , ( x + 2 ) , ( x + 3 )
Now, According to the given question:
---------------------------------------------------
= x + x + 1 + x + 2 + x + 3 = 46
4x + 6 = 46
4x = 46 - 6
4x = 40
x = 40/4
↪x = 10
◾Hence the Integers are 10 , 11 , 12 and 13 respectively.
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