Question

if sum of four consecutive numbers of AP is 26 and their product is 3960 then find the number

Answer 1

Answer:

Let the four numbers be a-3d,a-d,a+d,a+3d

a-3d+a-d+a+d+a+3d=26

4a=26

a=13/2

(a-3d)*(a-d)*(a+d)*(a+3d)=3960

(a^2-9d^2)*(a^2-d^2)=3960

(169/4-9d^2)*(169/4-d^2)=3960

and then solve it further

Step-by-step explanation: