if sum of magnitude of forces acting at a point is 16 N.if their resultant is normal to smaller force and has a magnitude of 8 N. the forces are
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Q is the smaller force , P is the other force, R is the resultant of( P & Q). Angle between R & Q is 90 °
Therefore, R ^2 = P^2 - Q^2 = ( P+ Q)(P-Q).
8^2 = 16( P-Q)
P -Q = 4 & P+Q = 16.
So P = 10 & Q = 6
Explanation:
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