If sum of n terms is 3n2-2n find the nth term and 10th term
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Answered by
0
Answer:
Tn=6n-5
T10=55
Step-by-step explanation:
Sn=3n^2-2n
S1=3(1)^2-2(1)
T1=1
S2-S1=T2
3(2)^2-2(2)-1=T2
T2=7
T2-T1=d
d=6
Now, Tn=a + (n-1)d
Tn=1+(n-1)6
Tn=6n-5
Now, S10 - S9 =T10
{3(10)^2-2(10)} - {3(9)^2 - 2(9)}= T10
{300-20} - {243-18}=T10
280-225=T10
55=T10
Answered by
2
Answer:
Answer:
Tn=6n-5
T10=55
Step-by-step explanation:
Sn=3n^2-2n
S1=3(1)^2-2(1)
T1=1
S2-S1=T2
3(2)^2-2(2)-1=T2
T2=7
T2-T1=d
d=6
Now, Tn=a + (n-1)d
Tn=1+(n-1)6
Tn=6n-5
Now, S10 - S9 =T10
{3(10)^2-2(10)} - {3(9)^2 - 2(9)}= T10
{300-20} - {243-18}=T10
280-225=T10
55=T10
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