if sum of n terms of a series be 3nsquare + 5n find its 10th term
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Answered by
3
If you know Sn then Tn is given by the formula (Sn)-(Sn-1).
so now since we want T10 we require to do
T10= (S10) - (S9)
=( 3*10^2 + 5*10) - (3*9^2 + 5*9)
=350 - 288
=62
so now since we want T10 we require to do
T10= (S10) - (S9)
=( 3*10^2 + 5*10) - (3*9^2 + 5*9)
=350 - 288
=62
Answered by
1
3n² + 5n
if we substitue n = 1, we will get 1st term.
3(1)² + 5(1)
= 3 + 5
= 8
n=2 - first term we get second term.
3(2)² + 5(2)
12 + 10
=22
sum of 2 terms = 22
second term = 22-8
= 14
common difference = second term - first term
= 14 -8
d = 6
now 10th term common formula = a + 9d
10th term = 8 + 9(14)
=8 + 126
= 134
134 is the 10th term.
hope it helps!!!!!
if we substitue n = 1, we will get 1st term.
3(1)² + 5(1)
= 3 + 5
= 8
n=2 - first term we get second term.
3(2)² + 5(2)
12 + 10
=22
sum of 2 terms = 22
second term = 22-8
= 14
common difference = second term - first term
= 14 -8
d = 6
now 10th term common formula = a + 9d
10th term = 8 + 9(14)
=8 + 126
= 134
134 is the 10th term.
hope it helps!!!!!
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