if sum of 'n' terms of an A. P is 3n²+5n and nth term is 164, then n =?
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Answer:We will subtract sum of n+1
Th term from sum of nth term to get 164
Step-by-step explanation:
3(n+1)^2+5(n+1)-3n^2-5n=164
6n+6=164
6n=158
N=158/6
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