If sum of n terms of an AP is 5n-n^2 find AP
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Given
we have given sum of n terms of an AP is 5n-n²
To Find
We have to find AP
Sₙ = 5n-n²
put n=1
S₁= 5(1)-(1)²
S₁= 5-1=4
put n = 2
S₂= 5(2)-(2)²
S₂=10-4
S₂=6
Since , S₁=a₁
So ,first term (a) is 4
First term + second term = S₂
=>a+ a₂ = 6
=>4+a₂=6
=>a₂= 6-4
=>a₂=2
Therefore, a= 4 & a₂=2
Now,we have to find the common difference
d= a₂-a
d=2-4
d= -2
AP= a,a+d,a+2d,a+3d
AP= 4,4+(-2),4+2(-2),4+3(-2)
AP=4,2,0,-2 ..
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