if sum
of n terms of AP is 3n square /2 +5n/2 then find it's 28th term
Answers
Answered by
0
Answer:
28th term is 235
Step-by-step explanation:
Let Sn = 3n²+5n/2
S28 = 3(28)²+5(28)/2 = 1246
S27 = 3(27)²+5(27)/2 = 1011
S28-S27 = 28th term
therefore 28th term is 235
Answered by
1
Answer:
85
Step-by-step explanation:
given Sn=(3n^2+5n)/2
we know that Sn-S(n-1)=An
so S28-S27=A27
S28-S27=(3*28*28+5*28)/2-(3*27*27+5*27)/2
=(2352+140)/2-(2187+135)/2
=1246-1161=85
so A28=85
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