if sum of P terms of an ap is 3 p square + 4 p.. find its n thh term
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Answer:
6n +1
Step-by-step explanation:
Sp = 3p2 + 4p
tn ⇒ Sn - Sn-1
= (3n2 + 4n) - [3(n-1)2 + 4(n-1)]
= (3n2 + 4n) - [3(n2 - 2n + 1) + 4(n-1)]
= (3n2 + 4n) - [3n2 - 6n + 3 + 4n - 4]
= (3n2 + 4n) - [3n2 - 2n - 1]
= 3n2 + 4n - 3n2 - 2n + 1
= 6n + 1
Therefore the nth term is 6n + 1.
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notsogenius4:
how to do it
For Sp we have 3n2 + 4p So for Sn it will be 3n2 +4p then if we find the sum of n terms and subtract it from its Sn-1 we will get Tn
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