If sum of product of two numbers qre 36 and 128 respectevly find the number
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let first number=x
second number=y
x+y=36-eq(i)
x×y=xy=128
(x+y) ^2=(x-y) ^2+4xy
(36) ^2=(x-y) ^2+4(128)
1296-512=784=(x-y) ^2
(x-y) =√(784) =28-eq(ii)
by adding (i)+(ii)
x+y=36
x-y=28
——————
2x=(36+28)
——————
x=(64/2)=32
y=36-x=36-32=4
so, x=32,y=4
..........hope this may help you........
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