Question

If sum of roots of 7x² + px - q = 0 is 7, then p =​

Answer 1

p = - 49

• The sum of roots of the equation is given 7. Now we know that sum of roots of the quadratic equation $ax^{2}+bx+c$ = 0 is  $-\frac{b}{a}$ .

• Hence comparing this to the given equation we get a = 7 , b = p and c = -q. So the sum of roots is $-\frac{p}{7}$

• So according to the problem $-\frac{p}{7}$ = 7, which implies p = - 49