if sum of roots of equation 5x^2-4x+2+k(4x^2-2x-1) =0 is 6 then find k
Answers
Answered by
0
Step-by-step explanation:
Correct option is
D
11
−13
Given equation is 5x
2
−4x+2+k(4x
2
−2x−1)=0
⇒x
2
(5+4k)−x(2k+4)+2−k=0
Hence, sum of the roots is
4k+5
2k+4
=6
Therefore, 2k+4=6(4k+5)
⇒2k+4=24k+30
⇒−26=22k
⇒k=
22
−26
⇒k=
11
−13
Answered by
0
Answer:
1.56
Step-by-step explanation:
(5×6)^2 -4×6 +2+k ( 4×6^2- 2×6-1) =0
30^2- 24+2 +k( 24^2- 12-1 )= 0
900-22 + k( 576- 13)= 0
878+ k( 563)= 0
563k = -878
k= -878/563
= -1.56
Hope it helps you.
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