if sum of roots of equation x²+px+q=0 is equal to sum of their squares then,
(a)p²-q²=0
(b)p²+q²=2q
(c)p²+p=2q
(d)none of these
plssss ans!!!!
Answers
Answered by
1
The sum of roots of equation x^2+px+q=0 is equal to sum of their squares, then prove that: p(p+1)=2q.
Answered by
2
Answer:
Let a and b be the roots of the equation x2 + px + q = 0Then, a + b = -p, ab= q.
According to the question,
a + b = a2 + b2
⇒ a + b= (a + b)2 - 2ab
⇒ -p = p2 - 2q
⇒ p2 + p = 2q
(c) is the answer
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