If sum of roots of the equation x2 - (k+6) + 2(2k-1)=0 is equal to half of their product, then find k.
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On comparing the given equation with a×2 +b× +c =o
Hera, a =1,b=-(kt6),c=2(2k-1)
sum of roots =6/a
sum of roots =-(k+6)/1
sum of roots=k+6
product of roots =c/a
product of roots =2(2k-1)
product of roots =4/c-2
Give: sum of roots 1/2 product of roots
k+6=1/2 (4k-)
2(k+6)=4k-2
2k+12 =4k-2
2k-4k=-2-12
-2k=14
2k=14
k=14/2
k=7
Hence , the value of k is 7
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