Question

If sum of square of 2 number is more then 112 by sum of there square

Answer 1

Answer:

ab = -56

Step-by-step explanation:

Let the numbers be a and b

(a^2) + (b^2) = (a + b)^2 + 112

a^2 + b^2 = a^2 + b^2 + 2ab + 112

2ab = -112

ab = -56