if sum of square of zeroes of quadratic polynomial f(x) =x²-2x-k is 20 then find the value of k
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Answer:-
Given Polynomial : x² - 2x - k.
Let , a = 1 , b = - 2 and c = - k.
Let the zeroes of the equation be α and β.
We know that,
Sum of the zeroes = - b/a
→ α + β = - ( - 2) / 1
→ α + β = 2 -- equation (1)
Product of the zeroes = c/a
→ αβ = k / - 1
→ αβ = - k -- equation (2)
Also given that,
Sum of squares of the zeroes = 20
→ α² + β² = 20 -- equation (3)
We know that,
(a + b)² = a² + b² + 2ab
Hence,
( α + β )² = α² + β² + 2αβ
Putting the values from equations (1) , (2) & (3) we get,
→ (2)² = (20) + 2 * ( - k)
→ 4 = 20 - 2k
→ 4 - 20 = - 2k
→ - 16 = - 2k
→ - 16/ - 2 = k
→ k = 8
Therefore, the value of k is 8.
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