Question

If sum of square of zeros of quadratic equation x^2-8x+k is 40 then find the value of k.

Answer 1

Let, zeroes of polynomial be a and b.
now, a²+b² =40
( a+b )² - 2ab =40
{ a+b= 8 and ab=k}
then, (8)² -2(k) =40
64 - 2k =40
-2k =40-64
-2k = -24
k=12
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