if sum of square of zeros of quardetic polynomial f(x) =x2-8x+k is 40 find the value of k
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Answer: x² -8x +k = f(x)
α= -b/a = 8
β= c/a = k
α+β =40 [ given in the question ]
8+K=40
K= 40-8
K= 32
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