If sum of squares of residual is 64 and degree of freedom is 6
then mean squares is
10.69
10.67
10.63
10.65
Answers
Answer:
10.65 I think
Explanation:
We look at an alternative test, the analysis of variance (ANOVA) test for the slope
parameter, H0 : m = 0, of the simple linear model,
Y = b + mX + ,
where, in particular, is N(0, σ2
), where the ANOVA table is
Source Sum Of Squares Degrees of Freedom Mean Squares
Regression SSReg =
P(ˆyi − y)
2 1 MSReg =
SSReg
1
Residual SSRes =
P(yi − yˆi)
2 n - 2 MSRes =
SSRes
n−2
Total SSTot =
P(yi − y)
2 n - 1
where
f =
MSReg
MSRes
,
with corresponding critical value fα(1, n − 2). Related to this, the average of the y
y
_
y = m x + b ^
y
^
y
total
deviation
unexplained deviation
explained deviation
^
Figure 6.13: Types of deviation
variable, ¯y, is a kind of baseline and since
(y − y¯)
| {z }
total deviation
= (ˆy − y¯)
| {z }
explained deviation
+ (y − yˆ)
| {z }
unexplained deviation
,
then taking sum of squares over all data points,
X(y − y¯)
2
| {z }
total variation
=
X(ˆy − y¯)
2
| {z }
explained variation
+
X(y − yˆ)
2
| {z }
unexplained variation