Question

If sum of squares of two consecutive even number is 100 then what are the numbers

Answer 1

Answer:

Step-by-step explanation:

let numbers be x and x+2

given that

$x^{2} +(x+2)^{2} = 100$

$x^{2} +x^{2} +4x+4$ =100

$2x^{2} +4x=96$

x(x+2) = 48

$x^{2} + 2x - 48=0$

therefore, solving we get

x = 6, -8

therefore the numbers are 6, 8 or -8, -6

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