Question

If sum of squares of zeroes of a quadratic polynomial p (x)= x^2-8x+l is 40.find the value of k

Answer 1

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Answer 2

k = 12

Step-by-step explanation:

Let a and b are the zeroes of polynomial $p (x)= x^2-8x+1$. Sum of zeroes is given by :

$a+b=\dfrac{-(8)}{1}=8$ .....(1)

$ab=k$

It is given that, $a^2+b^2=40$

It can be simplified as :

$(a+b)^2-ab=40$

From (1) we have,

$8^2-2k=40\\\\2k=64-40\\\\k=12$

So, the value of k is 12.

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Quadratic polynomial

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