Math, asked by kavya1971, 1 month ago

If sum of squares zeroes of polynomial f(x)=x2-8x+k is 40.Find k​

Answers

Answered by neelamjoshi962
0

Step-by-step explanation:

may be 30 is the correct answer

Answered by YagneshTejavanth
2

Answer:

Value of k is 24.

Step-by-step explanation:

Given :

Sum of squares of zeroes of the polynomial f(x) = x² - 8x + k is 40

Let α, β be the zeroes the given polynomial

So, Sum of squares of zeroes = α² + β² = 40

Comparing the given polynomial with ax² + bx + c we get

a = 1

b = - 8

c = k

Sum of zeroes = α + β = - b/a = - ( - 8 ) / 1 = 8

Product of zeroes = αβ = c/a = k/1 = k

We know that

( α + β )² = α² + β² + 2αβ

Substituting the known values

( 8 )² = 40 + k

64 = 40 + k

k = 64 - 40

k = 24

Therefore the value of k is 24.

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