If sum of the 3 consicative terms of an A.P.is 30 & their product is 360.Find the terms.
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Answer:
119,120,121
Step-by-step explanation:
let assume that the three terms be
a-d,a,a+d
as per 1st condition
(a-d)+(a)+(a+d)=360
3a =360
a =360/3
a=120
put the value of a in euqation
120-d+120+120+d =360
d^2= 360/360
d^2=1
d=1
a-d=120-1=119
a=120
a+d=120+1=121
three consecutive terms are 119,120,121
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