If sum of the 3rd and 8th term of an ap is 7 and the sum of the 7th and 14th term is -3.find the 10th term
Answers
Answer:
3rd term(a3)=a+2d
8th term(a8)=a+7d
14th term(a14)=a+13d
10th term(a10)=a+9d
Given the sum of the 3rd and 8th term is 7.ie,
( a+2d)+(a+7d)=7
2a+9d=7--------(1)
Also the sum of the 7th and 14th term is -3.ie,
(a+6d)+(a+13d)=(-3)
2a+19d=(-3)-------(2)
By subtracting eq(2) from (1)
2a+9d=7. 2a+9d=7
- {2a+19d=(-3)} -2a-19d=+3
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0(-10)d=10
d=10\(-10)
d=(-1)
Substituting the value of d to any one equation
2a+9d=7
2a+9x(-1)=7
2a-9=7
2a=7+9
2a=16
a=16/2
a=8
Therefore a10=a+9d
=8+9x(-1)
=8+(-9)
=8-9
=-1
Therefore 10th term a10 = -1
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